The market for industrial networking is still strong according to a new report from IMS Research, an independent provider of market research and consultancy. An estimated 31 million new fieldbus and Ethernet nodes were installed worldwide in 2011; this number is forecast to grow by an average of 10% a year, to just over 45 million new connected nodes in 2015.
The report, “The World Market for Industrial Networking – 2011 Edition”, forecasts that, in EMEA and the Americas, new connected nodes will grow fastest in servo and inverter drives. Their grow rate will be 11.8% a year, resulting in 3.5 million inverter drives and 0.8 million servo drives being connected to a network in 2015.
“These new network nodes will grow so fast because of the high growth in shipments of servo and inverter drives” explains Graham Brown, a market analyst. “Drive shipments are growing quickly in all regions, although the industry sectors creating this growth differ by drive type and region. The adoption of medium-voltage drives, for example, is growing in the oil and gas industry; growth in shipments of servo drives is in the machine-tool industry.”
While shipment growth is a key factor, IMS Research is also seeing a steady increase in the percentage of drives that are network-enabled and connected. The current focus on improving energy efficiency in factories is largely due to the potential reduction in running costs it offers; this may also be legislated in the coming years. Networked drives offer an effective means of improving overall factory efficiency; the number of new networked drives will likely increase by a substantial amount if such legislation is introduced. However, this is not likely to happen before 2015.
Many more networked drives are forecast to be shipped in Asia Pacific, partly because of many new greenfield projects. IMS Research projects that there will be about 4.3 million new servo and inverter drives networked in this region; equating to a growth rate of well over 15% a year, significantly above the world average rate.
“This is not surprising.” commented Brown. “Since 2009, several countries in Asia, especially China, have enjoyed strong economic growth. Heavy spending on industrial and infrastructure projects means that markets for several industrial products, particularly operator terminals and industrial PCs, are also growing quickly at over 14% a year. This suggests that the strong growth already seen in automation and in turn industrial networking in Asia Pacific is likely to continue.”
DrivesMag is working hard to better understand how automation, control and drives are currently being designed into and used in key industrial and manufacturing markets, assessing impact that they might have on the processes and value that they bring to users. Our focus this month is on the Batch and Specialty Chemical Markets.
If you are an expert in the field of chemical production, we'd like to ask you a few questions and will pay you for your time. Of course, we'll share our findings with you.
If you would like to participate in this study, please email us at This e-mail address is being protected from spambots. You need JavaScript enabled to view it for a link. The survey should take no longer than 20 minutes to complete. When you have finished, you can choose to be paid $45 for your time, or to give the $45 plus a $10 matching donation from DrivesMag to one of three great charities. Your answers will remain anonymous and combined with answers from others in a final report that you can choose to receive. Nobody will contact you afterwards to sell anything.

Power Factor (PF) is an important measure for electrical systems and it is defined as ratio of Real or Active Power, in total kilowatts, to total Apparent Power, in kilovolt amps.

The Power Factor topic is of interest to a large number of people. An Internet search with one of the search engines gave more than three million hits. There sometimes seems to be confusion between the terms Power Factor and cosj (phi). Just remember that the cosj is equal to Power Factor only in cases where both system voltage (U) and system current (I) are sinusoidal (cosj is equal to Power Factor only when the voltage and current considered are at the same frequency). In real-world electrical installations, both voltages and currents contain harmonics and the Power Factor is not equal to cosj.
To understand Power Factor, it can help to consider phasor diagrams. An electrical circuit under consideration is shown in Fig. 1. The supply voltage U connected to the circuit is at a single frequency; that voltage causes current I to flow through the components. According to Ohms law, the voltage drop in each component is calculated by multiplying the current I (in Amps) by the resistance (in Ohms). The phasor diagrams for this circuit are shown in Fig. 2.

Figure 1. The three basic linear electrical components in serial connection with the voltage U, causing the current I to flow through the circuit. The components are:
The voltages and currents in Fig. 1 can be illustrated in phasor form in Fig. 2. The current I is common for each component in the system, but the voltages are of different magnitude and their phasors are in different directions -- 90 degrees apart from each other’s. The three diagrams in Fig. 2. show the steps for defining the voltage phasors and the angle between the total voltage U and the current I. As result, we get the definition for the cos j:


Figure 2. The current phasor I rotates in phase with the voltage vector uR, but it is lagging the voltage phasor uL and leading the voltage phasor uC. All phasors rotate counter-clockwise. Because the uL and uC are pointing in opposite directions, they are subtracted and the difference uX is the reactive component of the total system voltage. The uR is the active or real component and the phasor sum of these voltages is the total voltage U. The cosine of the angle j between total voltage U and the active voltage uR is the Power Factor of an ideal system, which is known as cosj. If U and uR have one single, fundamental frequency, cosj is sometimes called displacement Power Factor.
To understand, power factor is sometimes visualized with a horse pulling a railroad car down a railroad track. Because the railroad ties are uneven, the horse must pull the car from the side of the track. The horse is pulling the railroad car at an angle to the direction of car’s travel. The power required to move the car down the track is the real power. The effort of the horse is the total (apparent) power. The car will not move sideways. Therefore the sideways pull of the horse is wasted effort or reactive power. These three different power vectors are shown in Fig. 3.

Figure 3. The Power factor definition by using power vectors
In summary:
Power plant generators usually are designed for PF = 0.8 to 0.9. Therefore, if the actual demand-side Power Factor is lower than the designed (0.8), either the generator current increases above the rated current or the active power output has to be limited. For that reason, the power companies put limits on reactive power consumed by the customers. The limits usually are set for large industrial or public customers only.
Customers have to pay a power factor penalty if power factor falls below a certain limit. The limits can vary widely from 0.8 to 0.97. Electric motors connected to the power line is the main reason for reduced power factor. The rated power factor of a standard motor depends on its rated power and, typically, is around 0.85 but can be much lower if the motor is lightly loaded. This topic will be studied in the next section.
The use of AC induction motors is essential for industry and utilities. AC induction motors consume more than 50 per cent of the energy used in industry. As compared to other type of loads, motor loads have relatively poor power factor. Poor power factor causes higher line currents, which causes additional heat in line cables and transformers. The power factor is especially low in cases when the motors are oversized and are running with a light load.

Figure 4. Line current and power factor of a 55 kW AC induction motor as function of the motor load.
To produce the required rotating torque and speed, the induction motor takes both active current and reactive current from the power supply. The rotating torque of the motor is created as an interaction between the active current component and the magnetic field. The field is produced by the reactive current component. Light load takes less active current but the magnetic field, as well as the reactive current, stays constant. This means that the power factor decreases with decreasing load, as shown in the Fig. 4. At the full load, the current is mainly active but, at the light load, the current is mainly reactive.There are many different methods to improve the power factor or compensate for the reactive power:
On a so-called PWM (Pulse Width Modulated) drive with a diode bridge converter input, the Power Factor to the AC line is near unity (see Fig. 5). The output may have an inductive (lagging) power factor, due to the motor’s inductive reactance. However, the motor’s reactive current is circulated between the motor and the inverter bus capacitors – and not to the input line.

Figure 5. A Variable speed AC drive input consists of a rectifier bridge that converts the line AC voltage to DC voltage. The smoothing of the DC voltage is made via an inductor (L) and capacitor (C). The DC voltage (Ud) then is converted in the inverter to variable frequency and variable voltage AC that is connected to the AC motor. The switches V1 to V6 in the inverter are very fast semiconductors, usually IGBT’s (Insulated Gate Bipolar Transistors) in modern drives.
Because of the fast switching inside the AC drive, there is a risk of electromagnetic emissions. Emissions can be both conductive and radiating interference. International regulations set limits on both low- and high-frequency emissions. With the use of filters, screening and suitable mechanical construction inside the drive cabinet, it is possible to meet the Electromagnetic Compatibility (EMC) standards.
Let’s study the currents of the above mentioned 55 kW/400V motor and drive system:
Motor: Motor Mechanical Power = 55 kW,
Input U = 400 V, efficiency = 94.4% and power factor = 0.89
Motor Electrical Input Power= 55 kW/0.944 = 58.3 kW
Motor Electrical KVA = kW/PF = 65.5

AC drive: Output P = 58.3 kW, 94.5 A
Input U = 400 V, efficiency = 98% and power factor = 0.96
Drive Input Power = 58.3 kW/0.98 = 59.5 kW
Drive Input KVA = 62.0
One can see that the drive input current from the supply is 5 amps, or more than five percent (94.5 versus 89.5 amps), lower than the drive output current to the motor. The active power input, instead, is 1.2 kW (58.3 versus 59.5 kW) higher than the output from the drive.
The difference in drive input and output power factor is how the variable speed AC drive can improve the Power Factor and how the drive output current can be greater than the input current!
The power losses in the power line, transformers and cables are proportional to the square of the current. We can estimate the following:
Assume the average load on the 55 kW motor is 35 kW.
From Fig. 4, the motor current at 35 KW is 65 amps; the AC drive input current
under these conditions is 60 amps.
The AC drive reduces the input current from 65 A to 60 A.
The reduction of losses when operating the motor from an AC drive is then:
If total losses on the supply side are 5% of the average load, the AC drive can reduce the losses to about 4%. The reduction on the total power consumption, as well as reduction on money spent, is one per cent.
(Note: The original reason to install an AC drive is not the power factor improvement but better process controls, energy savings in the process, and/or reduced wear of the machinery. PF improvement is a positive side effect.)
The main difference between standard AC and DC drives is that PWM AC drives have a diode rectifier on the front end while DC drives have SCR rectifier. The control principle of the SCR rectifier is based on phase control with line commutation, causing a phase shift between voltage and current. The lower the speed, the larger the phase shifts. This reduces the power factor of DC drives, especially in the lower speed ranges (as shown in Fig. 6).
Figure 6. Power factor of AC and DC drives as function of motor speed. The power factor topic is interesting and important for a number of parties within the power generation and consumption marketplace:
In my last post, I took a look at the results of some research I did regarding variable speed drive efficiency and motor efficiency. In this post, I’ll take a look at why designers, in particular, building system designers, are driven to apply variable speed technology in their systems. This, combined with the previous post, will lay the foundation for the next post, where I will look at what happens when you apply a VFD to motor serving a centrifugal machine in an HVAC system. Its mostly good news, but there are a few surprises.
Variable Speed and Building System Loads
For folks like me in the building industry, VSDs in general and VFDs in particular are just about always applied to a centrifugal machine like a fan or a pump or a centrifugal chiller. To some extent, the ability to vary the speed of a centrifugal machine as the demand on it changes is “God’s gift” to the industry because for HVAC and other building systems, just about everything varies all of the time. Here is an example.

What you are looking at is the daily and seasonal load profile for a facility in Southern California that we developed using the building trend data.

We were going to add chiller capacity and instead of doing a model, we let the building tell us what the best chiller size would be and what “sweet spot” we should target on its performance curve by picking hourly flow and temperature data (which we knew was reliable) and doing the math.